++ 50 ++ cosθ=√3/2 303690

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/3 b−4/5c −4/3 d 4/5 3)Given sin(−θ)=−1/6 and tanθ=−35/√35 What is the value of cosθ?a−35/√210 b−35/√6 c35/√210 d35/√6 4)cos(−θ)=3/√4, sinθ2 Solutionsto Exercises Problem Set 11, page 8 1he combinationsgive (a) a line in T R3 (b) a plane in R3 (c) all of R3 2 v w= (2 ,3) and −= (6 1) will be the diagonals of the parallelogram with v and w as two sides going out from (0,0) 3 This problem gives the diagonals v wand − of the parallelogram and asks for the sides The opposite of Problem 2

Cosθ=√3/2

Cosθ=√3/2-Sinθ cosθ = (√3 1)/2 Squaring both the sides sin 2 θ cos 2 θ 2 sinθ cosθ = (3/4) (1/4) 2 × (1/2) × (√3/2) 1 2 sinθ cosθ = (3/4) (1/4) (√3/2) 2 sinθ cosθ = √3/2 sin2θ = √3/2 (2 sinθ cosθ = sin2θ) ⇒ 2θ = 60° ⇒ θ = 30° Now, tanθ = tan30° ⇒ 1/√3 Dear student, solution to you question is here – Cosθ = √3/2 = cos 30° = θ = 30° So, the value of θ is 30°

If Pi 2 8 P And Sin 8 4 5 Find The Exact Value Of Cos8 And Cot8 Socratic

If Pi 2 8 P And Sin 8 4 5 Find The Exact Value Of Cos8 And Cot8 Socratic

Answer √2 Proof Let P be the point (x₁, y₁) and Q the point (x₂, y₂) in a plane Let the axes be at right angles to one another (rectangular)Share It On Facebook Twitter Email 1 Answer 1 vote answered by Anik (710k points) selected by Vikash Kumar Best answer I/3 = 1/6 I = 1/2 I = 05Answer (1 of 2) Instead of theeta let us use A SinA = √3/2 => cosec A=2/√3 CosA =√(1sin^2 A) = √(1 3/4) =√(1/4)= 1/2 CotA = CosA/Sin A = (1/2)/(√3/2

 Given sin θ cos θ = √2 cos θ Dividing both the RHS and LHS by cos θ, we get θ θ θ θ θ θ s i n θ c o s θ c o s θ c o s θ = 2 c o s θ c o s θ Since θ θ θ t a n θ = s i n θ c o s θ, the above equation can be written as tanθ 1 = √2 tanθ = √2 1 Download Solution PDF cosΘ=(√55)/8 tanΘ=(3√55)/55 cscΘ=8/3 secΘ=(8√55)/55 cotΘ=(√55)/3 Since sin is positive and cos is less than 0, it means that this triangle is in quadrant 2 Use Pythagorean's theorem (a^2b^2=c^2) and plug in your given values a=3 and c=8 and solve 3^2b^2=8^2 → 9b^2=64 → b^2=55 → b=√55 (it is negative because it is in quadrant 2 and the cos is the xShare It On Facebook Twitter Email 1 Answer 1 vote answered by Chandan01 (512k points) selected by Anika01 Best answer Let AB =k√3 and BC = 2k In right

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If √3 cosθsinθ=√2then general value of θ is nπ−1n π4n I f √3 cosθsinθ= √2,then general value of θ is A nπ(−1)n π 4,n∈ Z B (−1)n π 4− π 3,n∈Z C nπ π 4− π 3,n∈ ZIf cosec θ=2 show that cotθsinθ1cosθ = 2 cosecθ=2to If cosec θ = 2 , show that ( c o t θ s i n θ 1 c o s θ ) = 2 Please scroll down to see the correct answer and solution guide

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